Question 894327
{{{sqrt(3x-2)+3=4x}}}
{{{sqrt(3x-2)=4x-3}}}
{{{3x-2=(4x-3)^2}}}
{{{3x-2=16x^2-24x+9}}}
{{{16x^2-27x+11=0}}}
{{{(x-1)(16x-11)=0}}}
Two solutions:
{{{x-1=0}}}
{{{x=1}}}
Verifying,
{{{sqrt(3-2)+3=4}}}
{{{1+3=4}}}
{{{4=4}}}
True.
{{{16x-11=0}}}
{{{16x=11}}}
{{{x=11/16}}}
Verifying,
{{{sqrt(3(11/16)-2)+3=4(11/16)}}}
{{{sqrt(33/16-32/16)+3=11/4}}}
{{{sqrt(1/16)+12/4=11/4}}}
{{{1/4+12/4=11/4}}}
{{{13/4=11/4}}}
False, this is the extraneous solution.