Question 894224
This works exactly the same way as with numbers without variables.


For clarity, show like this:
{{{(-2t)/(3(t-5))=(n)/(6(t-5))}}}


You want to know how to multiply the left member by some {{{1=k/k}}} so that the denominator will become {{{6(t-5)}}}.  How will this be done?  What is k?


{{{3(t-5)*k=6(t-5)}}},  what is k?
{{{k=(6(t-5))/(3(t-5))}}}
{{{k=6/3}}}
{{{highlight_green(k=2)}}}.


Do the same thing to the numerator:
{{{-2t*2=-4t}}}


The equivalent value for n is {{{-4t}}}.
The fraction is {{{highlight((-4t)/(6(t-5)))}}}.