<PRE><B>Question 894263</B>
three men do a job in 12 days.
Two of the men work twice as fast as third.
How long will it take one of the faster men.
:
let t = time required by one of the faster men to do the job alone
then
2t = time required by the slower guy
:
Let the completed job = 1
:
A shared work equation
{{{12/t}}} + {{{12/t}}} + {{{12/(2t)}}} = 1
multiply thru by 2t
2(12) + 2(12) + 12 = 2t
24 + 24 + 12 = 2t
60 = 2t
t - 60/2
t = 30 days for one of the faster guys to do the job
:
:
you can check this for yourself
{{{12/30}}} + {{{12/30}}} + {{{12/(60)}}} = </PRE>