Question 894248
You are looking for the variable point, (2,y); and use Distance Formula:


{{{sqrt((2-(-2))^2+(y-(-1))^2)=5}}}
{{{sqrt(16+(y+1)^2)=5}}}
{{{16+(y+1)^2=25}}}
{{{(y+1)^2=9}}}
{{{y+1=0+- 3}}}
{{{highlight(y=-1+- 3)}}}


y  is  -4  or  +2.