Question 894249
Q:
Find all points on the x-axis that are 5 units from the point (4,-3)
A:
We want to find all x such that the distance between the points (x, 0) and (4, -3) is equal to 5.
{{{sqrt((4 - x)^2 + (-3 - 0)^2) = 5}}}
Square both sides
{{{(4 - x)^2 + (-3 - 0)^2 = 25}}}
{{{(4 - x)^2 = 16}}}
Get the square root of both sides
4 - x = 4  or 4 - x = -4
x = 0 or 8
The points on the x-axis are (0, 0) and (8, 0).