Question 894146
Find four consecutive even integer
x, (x+2), (x+4),(x+6)
:
 such that the sum of twice the first,  five times the second, and four times the third divided by three times the fourth equals three.
{{{(2x + 5(x+2) + 4(x+4))/(3(x+6))}}} = 3
multiply both sides by 3(x+6)
2x + 5(x+2) + 4(x+4) = 3(3(x+6))
Distribute
2x + 5x + 10 + 4x + 16 = 9x + 54
11x + 26 = 9x + 54
11x - 9x = 54 - 26
2x = 28
x = 28/2
x = 14 is the 1st integer, 16, 18, 20 are the rest
:
;
See if that works
{{{(2(14)+5(16)+4(18))/3(20)}}} =
{{{(28+80+72)/60}}} = 
{{{180/60}}} = 3