Question 894166
Write the equation of the circle in standard form and give the center and radius.

4x^2+4y^2-4x-8y-1=0 
<pre>
Equation of circle, in center-radius form: {{{highlight_green(highlight_green((x - 1/2)^2 + (y - 1)^2 = 6/4))}}}
Center coordinates:  (h, k), or ({{{highlight_green(1/2)}}}, {{{highlight_green(1)}}})
{{{r^2 = 6/4}}}, so radius is: {{{sqrt(6/4)}}}, or {{{highlight_green(sqrt(6)/2)}}}
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