Question 894132
{{{sqrt(x+1)+5=x}}}
{{{sqrt(x+1)=x-5}}}
{{{x+1=x^2-10x+25}}}
{{{x^2-11x+24=0}}}

{{{(x-3)(x-8)=0}}}
Two solutions:
{{{x-3=0}}}
{{{x=3}}}
Verifying,
{{{sqrt(3+1)+5=3}}}
{{{2+5=3}}}
False, this is the extraneous solution.
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{{{x-8=0}}}
{{{x=8}}}
Verifying,
{{{sqrt(8+1)+5=8}}}
{{{sqrt(9)+5=8}}}
{{{3+5=8}}}
{{{8=8}}}
True.