Question 894092
{{{A+B=15}}}
{{{A*B=56}}}
From the first equation,
{{{A=15-B}}}
Substitute into the second,
{{{15-B)B=56}}}
{{{15B-B^2=56}}}
{{{B^2-15B+56=0}}}
{{{(B-7)(B-8)=0}}}
Two solutions:
{{{B-7=0}}}
{{{B=7}}}
then,
{{{A=56/7=8}}}
and
{{{B-8=0}}}
{{{B=8}}}
then,
{{{A=56/8=7}}}
The two numbers are 7 and 8.