Question 893870
your equation is 1 + (1/x^2) = 3/x)


multiply both sides of the equation by x^2 to get:


x^2 + 1 = 3x


subtract 3x from both sides of the equation to get:


x^2 - 3x + 1 = 0


use the quadratic formula to solve for x.


you will get x = (3 +/- sqrt(5)) / 2


this is equivalent to x = 3/2 +/- sqrt(5)/2


that should be selection a.


the quadratic formula is:


<pre>


x =                -b +/- sqrt(b^2 - 4ac)
                -------------------------------
                             2a

</pre>


your formula has to be in the standard form of ax^2 + bx + c = 0
your formula is x^2 - 3x + 1 = 0
you get:
a = 1
b = -3
c = 1


replace a and b and c in the formula and solve for x.