Question 893713
{{{sqrt(3x-2)<=2}}}
{{{3x-2<=4}}}
{{{3x<=6}}}
{{{x<=2}}}
However the argument of the square root function must be greater than or equal to zero.
{{{3x-2>=0}}}
{{{3x>=2}}}
{{{x>=2/3}}}
So then,
{{{2/3<=x<=2}}}