Question 893639
Use the Pythagorean theorem,
{{{t+1}}} is a side.
{{{(t-1)^2+(t+1)^2=4^2}}}
{{{t^2-2t+1+t^2+2t+1=16}}}
{{{2t^2+2=16}}}
{{{2t^2=14}}}
{{{t^2=7}}}
{{{t=sqrt(7)}}}
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{{{t+1}}} is the hypotenuse.
{{{(t-1)^2+4^2=(t+1)^2}}}
{{{t^2-2t+1+16=t^2+2t+1}}}
{{{-2t+17=2t+1}}}
{{{-4t=-16}}}
{{{t=4}}}