Question 75436
Factor:
{{{7a^2+17a+6}}} The factors will have the form: (?a+m)(?a+n)
First, what are the possible factors of the first term {{{7a^2}}}?
The only possibility here is:{{{7a^2 = 7a*a}}} so you can start with:
{{{(7a+m)(a+n)}}}
The m and n must meet the following requirements:
m*n = 6  This is the last term of the trinomial.
The possibilities are:
m = 3 and n = 2
m = 1 and n = 6
Let's try the first set.
{{{(7a+3)(a+2)}}} Using the FOIL method, multiply these factors.
{{{(7a+3)(a+2) = 7a^2+14a+3a+6}}} Simplify to get: {{{7a^2+17a+6}}} which is the original trinomial.
The factors are: {{{(7a+3)(a+2)}}}