Question 893508
That is a rational function.  Nothing to solve.  What do you really want from it?  What is x?  What is H(x) for some given x?


{{{highlight_green(H(x)=(8x)/(x(x^2-49)))}}}


It EXCLUDES any value if x=0, because H is undefined for x=0.
It has a vertical asymptotes for x=-7 and x=7, because H is undefined at those values.
H contains the factor, {{{x/x}}}, which is why x=0 is a hole, and not an asymptote.


You can check the signs of H around the critical x values so you can find where H is
positive and where negative, and how H behaves around the asymptote.  The critical values
of x are 0 and -7 and 7.


(This attempted graph is not rendering.  Try putting the function either into a graphing calculator or in the text search field of google.)

{{{graph(300,300,-12,12,-10,10,(8x)/(x(x^2-49)))}}}