Question 75436
can you please help me Factor the Following Quadratic:

 7a^2 + 17a + 6   
This is the arch, ac, or grouping method.  I've heard it called all three things.
This is in ax^2+bx+c form.  a=7, b=17, and c=6
We need to replace the b term with two numbers that multiply to give you a*c, but add to give you b.  Then we factor by grouping.
a*c=7*6=42
42=14*3 and 17=14+3, so....
7a^2+14a+3a+6  factor the GCF out of the first two and last two terms:
7a(a+2)+3(a+2) factor out (a+2)
{{{highlight((a+2)(7a+3))}}}
Happy Calculating!!!!