Question 893526
Find the area of a rectangle whose length is five less than four times its width and whose perimeter is thirty more than six times its width.
<pre>
Let width be W
Then length = 4W - 5
Perimeter = 2W + 2L, or 2W + 2(4W - 5), or 2W + 8W - 10, or 10W - 10
With given perimeter, we have: 10W - 10 = 6W + 30
10W - 6W = 30 + 10
4W = 40
W, or with = {{{40/4}}}, or 10
Length:  4(10) - 5, or 40 - 5, or 35
Area:    10(35), or {{{highlight_green(350)}}}