Question 893503
 Find the vertex, discuss the transformation from the parent graph and state the roots of f(x)=x^2+12x+35
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To find the vertex:
complete the square:
f(x)=(x^2+12x+36)-36+35
f(x)=(x+6)^2-1
This is the vertex form of equation for a parabola that opens upwards wit vertex at (-6,-1)
..
To find the roots, set f(x)=0
x^2+12x+35=0
(x+7)(x+5)=0
x=-7
or
x=-5
Roots are -7 and -5

see graph below as a visual check
{{{ graph( 300, 300, -10, 10, -10, 10, x^2+12x+35) }}}