Question 10281
The diagonal of the square is actually the diameter of the circle.  The length of this diaganal can be found by Theorem of Pythagoras:  {{{1^2 + 1^2 = d^2}}} so {{{d^2 = 2}}} and {{{d=sqrt(2)}}}.  The radius of the circle is half the diameter of the circle, which is {{{r = (sqrt(2))/2 }}}.  


Area of the circle {{{A=pi*r^2}}}, so {{{A = pi * ((sqrt(2))/2)^2= pi*2/4 = pi/2}}} square feet.  


If you need the decimal approximation, this would be about {{{3.14/2}}} or 1.57 square feet.


R^2 at SCC