Question 893290
You needed to use,
{{{y-y[1]=((y[2]-y[1])/(x[2]-x[1]))(x-x[1])}}}
or
{{{y-y[2]=((y[2]-y[1])/(x[2]-x[1]))(x-x[2])}}}
.
.
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{{{y-1=((-1-1)/(0-(-3)))(x-(-3))}}}
{{{y-1=((-2)/(3))(x+3)}}}
{{{y-1=-(2/3)x-2}}}
{{{y=-(2/3)x-1}}}