Question 893418
Answer 541176 by Alan3354(39037)   on 2014-08-17 14:28:45 (Show Source): 

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Differentiate y=2sin3x/(x-1)
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y = 2sin(3x)/(x-1)
y = 2sin(3x)*(x-1)^-1
Use the product rule
y' = 2cos(3x)*3(x-1)^-1 + 2sin(3x)*(-1)*(x-1)^-2