Question 893426
a.f'(x)
b.f"(x)
c.f"'(x)
d.f^(4)(x) 
f(x)= x^4-2x^3-3x^2+5x-7 
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f' = 4x^3 - 6x^2 - 6x + 5
f'' = 12x^2 - 12x - 6
f''' = 24x - 12
f'''' = 24
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See how that works?
f'(x^n) = {{{n*x^(n-1)}}}