Question 893389
The perimeter of a rectangular field is 60 meters. Its area is 2, square meters. What are its dimensions?
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2L + 2W = 60
L*W = 2 --> L = 2/W
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L + W = 30
2/W + W = 30
2 + W^2 = 30W
W^2 - 30W + 2 = 0
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*[invoke solve_quadratic_equation 1,-30,2]
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W = 0.0668154769319216 m
L = 29.9331845230681 m