Question 893394
Please answer this word problem: "The length of a rectangle is one more meter longer than its width. Its diagonal is 29 meters. Find the dimensions of the rectangle."
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s = length of the short side
{{{d^2 = s^2 + (s+1)^2}}}
{{{841 = 2s^2 + 2s + 1}}}
{{{2s^2 + 2s - 840 = 0}}}
{{{s^2 + s - 420 = 0}}}
(s + 21)*(s - 20) = 0
width = 20 meters
length = 21 meters