Question 893368
Number 2:

Factorize each term.
{{{1}}}....?
{{{8=2^3}}}
{{{27=2^3}}}
{{{64=8*8=2^3*2^3}}} or {{{2^6=4*4*4=4^3}}}
The rule appears for any n term, general term is {{{n^3}}}.


Number 6:

The sequence depends on the first two terms.  The n=1 and the n=2 terms are both 1.  The sequence follows as any n term is the n-1 term plus the n-2 term.  If you want to call any term as {{{T[n]}}}, then any n term starting at n=3 will be {{{T[n]=T[n-1]+T[n-2]}}}.