Question 893361
Consecutive Integers x, x+1, x+2.


The description, {{{x(x+2)=20+(x+1)}}}.
Simplify.
{{{x^2+2x=x+1+20}}}
{{{x^2+2x=x+21}}}
{{{x^2+x=21}}}
{{{x^2+x-21=0}}}


Will x really be an integer?


Discriminant:  {{{((-1)^2-4*1*(-21))=1+84=85}}}.  This is not a square.
The quadratic expression cannot be factored to have integer coefficients.
The numbers WILL NOT be integers.