Question 893267
LOGx + LOG(x-15) = 2 Solve for x.
Adding logs is multiply
{{{log((x(x-15))) = 2}}}
The exponent equiv
x(x-15) = 10^2
x^2 - 15x = 100
x^2 - 15x - 100 = 0
Factors to
(x - 20) (x + 5) = 0
only the positive solution is valid here
x = 20