Question 893279
An object is thrown with a velocity of v, in feet/second, from an initial height of s feet. The object's height at any time,t, in seconds, is given by h= -16t ²  + Vt+s.How long would it take an object thrown downward with an initial velocity of 25 ft/s from an initial height of 5280 ft to reach the ground? (Round your answer to the nearest tenth.)
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h(t) = -16t^2 + Vt + s
h(t) = -16t^2 - 25t + 5280
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It reaches the ground when h(t) = 0
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h(t) = -16t^2 - 25t + 5280 = 0
*[invoke solve_quadratic_equation -16,-25,5280]
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t = 17.4 seconds