Question 893072
p pounds of peat moss
v pounds of vermiculite


Total mixture:  {{{100+p+v}}}


Total peat moss:  {{{100*(0.12)+p}}}


Total vermiculite:  {{{100*(0.06)+v}}}


15% Peat Moss:  {{{highlight_green((100(0.12)+p)/(100+p+v)=0.15)}}}

15% Vermiculite:   {{{highlight_green((100(0.06)+v)/(100+p+v)=0.15)}}}


These are two linear equations in the two variables p and v.