Question 893085
 You can solve the given equation, which seems to be based on hourly rate of increase r every hour.


{{{log((50))=log((25))+log((r^5))}}}
{{{log((50))=5log((1+r))+log((25))}}}
{{{5*log((1+r))=log((50))-log((25))}}}
{{{log((1+r))=(1/5)log((2))}}}
Evaluating the right side in base ten,
{{{log((1+r))=0.060206}}}
{{{10^0.060206=r+1=1.15}}}


r=0.15, meaning rate is 15% each hour.