Question 892945
x to power of 2;
y to power of 1;
PARABOLA.


Solve for y and if needed, complete the square....

{{{y=-x^2-2x+1}}}
{{{y=-1(x^2+2x-1)}}}
Use the term, {{{(2/2)^2=1}}}.
{{{y=-1(x^2+2x+1-1-1)}}}-----add and subtract 1 inside the parentheses.
{{{y=-1((x+1)^2-2)}}}
{{{highlight(y=-(x+1)^2+2)}}}