Question 892906
{{{x^4+64y^4=(x^2-4xy+8y^2)(x^2+4xy+8y^2)}}}
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No further simplification is possible for {{{x^4+y^2+5}}}
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{{{x^4-11x^2y^2+y^4=(x^2-3xy-y^2)(x^2+3xy-y^2)}}}