Question 892912
{{{drawing(300,300,-2,12,-2,12,grid(1),graph(300,300,-2,12,-2,12,8x-10))}}}
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{{{drawing(300,300,-2,12,-2,12,circle(5/2,10,0.3),grid(1),graph(300,300,-2,12,-2,12,8x-10,-4x+20))}}}
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Algebraically,
{{{8x-10=-4x+20}}}
{{{12x=30}}}
{{{x=30/12}}}
{{{x=5/2}}}
Then,
{{{y=8(5/2)-10}}}
{{{y=20-10}}}
{{{y=10}}}
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The intersection point is (5/2,10).