Question 892835
<pre>
{{{x^2-6x+7}}}{{{""=""}}}{{{"0"}}}

{{{x^2-6x}}}{{{""=""}}}{{{-7}}}

Multiply {{{-6}}} by {{{1/2}}}, get {{{-3}}}
Square {{{-3}}} get {{{(-3)^2="" + 9}}}.
Add {{{""+9}}} to both sides:

{{{x^2-6x+9}}}{{{""=""}}}{{{-7+9}}}

Factor the left side, combine terms on right:

{{{(x-3)(x-3)}}}{{{""=""}}}{{{2}}}

Both factors are the same, so write as one of them squared.
Since 2 = 2!, write 2 that way:

{{{(x-3)^2}}}{{{""=""}}}{{{2!}}}

That's in the form {{{(x-a)^2}}}{{{""=""}}}{{{b!}}}, where

a and b are the integers 3 and 2 respetively, and 2 is written as
a factorial 2!.

Edwin</pre>