Question 892682
How long does it take a ball to reach the ground 7.0 m below, if it is thrown straight up with an initial speed of 2.0 m/s?
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9.8 m/sec/sec is commonly used for gravity's acceleration on Earth.
Height as a function of time is:
h(t) = -4.9t^2 + 2t + 7 h in meters, t in seconds
h(t) = 0 at impact
-4.9t^2 + 2t + 7 = 0
*[invoke solve_quadratic_equation -4.9,2,7]
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Ignore the negative value
t =~ 1.4166 seconds