Question 892414
volume of a cone, {{{(1/3)h*pi*r^2}}}


If similar cones, then h and r of each are in proportion.
Compare {{{(1/3)5pi*r^2}}} to {{{(1/3)20*pi((20/5)(r))^2=(1/3)20*pi(4r)^2}}};
Notice that the larger cone has height 4 times larger and radius also 4 times larger.


Compare smaller volume to larger volume, ratio is {{{((1/3)5pi*r^2)/((1/3)20pi(4r)^2)}}}
{{{(cross(1/3)5cross(pi)*r^2)/(cross(1/3)20cross(pi)(4r)^2)}}}
{{{(5r^2)/(20*16*r^2)}}}
{{{(5cross(r^2))/(20*16*cross(r^2))}}}
{{{5/320}}}
{{{highlight(1/64)}}}