Question 892431

hi,I am really worried about this division equation Could someone help me please?

(2x^3 + 7yx^3 + 4xy^2 - 3y^3) / (2x + 3y) 
<pre>
It appears you meant: {{{(2x^3 + 7yx^2 + 4xy^2 - 3y^3)/(2x + 3y)}}}. Notice that the 2nd expression in the DIVIDEND or
NUMERATOR was changed from {{{7yx^3}}} to {{{7yx^2}}}. 

 	        <u>x^2    +    2xy     -     y^2</u>            
      <u>2x + 3y</u> |2x^3    +   7x^2y    +   4xy^2   -    3y^3
	      |<u>2x^3    +   3x^2y</u> 
                           4x^2y    +   4xy^2						 
                           <u>4x^2y    +   6xy^2</u> 
                                    -   2xy^2   -    3y^3
			            <u>-   2xy^2   -    3y^3</u>	

The quotient for: {{{(2x^3 + 7yx^2 + 4xy^2 - 3y^3)/(2x + 3y)}}}  is: {{{highlight_green(highlight_green(x^2 + 2xy - y^2))}}}. This quotient CANNOT be factored further.