Question 891919
<pre>
That the combinations of 23 things taken 3 at a time.

{{{(23*22*21)(3*2*1)}}} = 1771

Notice that the top and bottom both contain 3 factors.
Each successive factor is one less than the preceding factor.
We begin the numerator with 23 and the denominator with 3.

This is sometimes written as C(23,3), 23C3, or {{{(matrix(2,1,23,3))}}}

But it means 1771.

Edwin</pre>