Question 892340
{{{(x+2)^2 = 49 }}}
{{{x+2 = 0 +- 7}}} 
{{{x=-2 +- 7}}}
{{{x=5}}} and {{{x=-9}}}
and
{{{(y+5)^2 = 16}}}
 {{{y+5=0 +- 4}}}
{{{y=-5 +- 4}}}
{{{y=-1}}} and {{{y=-9}}}
So then,
{{{x+y=5-1=4}}}
{{{x+y=5-9=-4}}}
{{{x+y=-9-1=-10}}}
{{{x+y=-9-9=-18}}}