Question 892320
The inverse relation would be to switch x and y.
{{{x^2+(y-3)^2=4}}}
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First, {{{(x-3)^2+y^2=4}}}
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{{{drawing(300,300,-3,6,-3,6,grid(1),circle(3,0,2),circle(3,0,0.2))}}}

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Then, {{{x^2+(y-3)^2=4}}}
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{{{drawing(300,300,-3,6,-3,6,grid(1),circle(3,0,2),circle(3,0,0.2),circle(0,3,0.2),circle(0,3,2))}}}