Question 892330
For an equilateral triangle,
{{{A=(sqrt(3)/4)s^2}}}
So if {{{s[2]=(1/2)s[1]}}}
{{{A[2]/A[1]=s[2]^2/s[1]^2}}}
{{{A[2]/A[1]=((1/2)s[1]^2)/s[1]^2}}}
{{{A[2]/A[1]=1/4}}}
Since the new area is {{{1/4}}} of the old area, the decrease is {{{3/4}}} or {{{75}}}%.