Question 892232
Given:  {{{2f(x) - 3f(1/x) = x^2}}}

let x = 2.  Then {{{2f(2) - 3f(1/2) = 4}}}
Let x = 1/2.  Then {{{2f(1/2) - 3f(2) = 1/4}}}
From the second equation, {{{f(1/2) = 1/8 + (3/2)*f(2)}}}.
Substitute this into the first:
{{{2f(2) - 3/8 - (9/2)*f(2) = 4}}}
==>  {{{(-5/2)*f(2) = 35/8}}} ==>{{{f(2) = -7/4}}}