Question 892231
THIS IS THE CORRECT SOLUTION AND PROCESS:


SIMPLER USE OF ELIMINATION


{{{x+9/y=13}}} AND {{{x-2/y=2}}}


Multiply all members by y.
{{{xy+9=13y}}}
{{{xy-13y=-9}}}
-
{{{xy-2=2y}}}
{{{xy-2y=2}}}
-
The system to solve using the elimination method is:
{{{system(xy-13y=-9,xy-2y=2)}}}
Eliminating the xy term is the easy part.  Here will be elimination of the y terms.
Multiply this way.
{{{system(2xy-26y=-18,13xy-26y=26)}}}


Subtract the first equation from the second equation:
{{{13xy-26y-(2xy-26y)=26-(-18)}}}
{{{11xy=26+18}}}
{{{11xy=44}}}
{{{highlight_green(xy=4)}}}
-
Going back to the earlier system and eliminating xy,
{{{xy-2y-(xy-13y)=2-(-9)}}}
{{{-2y+13y=11}}}
{{{11y=11}}}
{{{highlight_green(y=1)}}}


SOLUTION:  If y is 1, then xy=4 means x=1.




---
THE EARLIER POSTING HAD SOME MISTAKES AND WAS WRONG:
--DELETED--