Question 892160
{{{y=4x^3+3x^2-36x+6 }}}
{{{dy/dx=12x^2+6x-36}}}
{{{(d2y)/(dx2)=24x+6}}}
First off find the points where {{{dy/dx=0}}}
{{{12x^2+6x-36=0}}}
{{{2x^2+x-6=0}}}
{{{(x+2)(2x-3)=0}}}
Two solutions:
{{{x+2=0}}}
{{{x=-2}}}
and
{{{2x-3=0}}}
{{{2x=3}}}
{{{x=3/2}}}
Now,
{{{24(-2)+6=-48+6=-42}}}
and
{{{24(3/2)+6=36+6=42}}}