Question 892076
{{{r=sqrt(1^2+1^2)=sqrt(2)}}}
{{{cos(theta)=1/sqrt(2)=sqrt(2)/2}}}
{{{sin(theta)=1/sqrt(2)=sqrt(2)/2}}}
{{{1+i=sqrt(2)(cos(45)+i*sin(45))}}}
{{{(1+i)^4=(sqrt(2))^4(cos(4*45)+i*sin(4*45))}}}
{{{(1+i)^4=4(cos(180)+i*sin(180))}}}
{{{(1+i)^4=4(-1+i*0)}}}
{{{(1+i)^4=-4}}}