Question 75243
Distance(d)=rate(r) times time(t)or d=rt; t=d/r; r=d/t

Car A's average rate of speed=60mph
Car B's average rate of speed=50mph

When the distance car A has traveled plus the distance car B has traveled equals 440 mi, then the two cars are together. 

Car A's distance=rt(car A)=60t
Car B's distance=rt(car B)=50t

So:

60t+50t=440
110t=440  divide both sides by 110

t=4 hours------------------elapsed time 'till the two cars meet.

CK
60*4+50*4=440
240+200=440
440=440



Hope this helps---ptaylor