Question 891987
{{{highlight((n+2)^2=3(n-2))}}}



{{{n^2+4n+4=3n-6}}}
{{{n^2+n+10=0}}}
{{{n=(-1+- sqrt(1-4*10))/2}}}---- Not likely what you want, unless you allow for imaginary parts.


<i>difference of the number and 2</i>  ?
This could mean, {{{2-n}}}.
This way gives you {{{n^2+4n+4=3(2-n)}}}
{{{n^2+4n+4=6-3n}}}
{{{n^2+7n-2=0}}}
{{{n=(-7+- sqrt(49+4*2))/2}}}
{{{n=(-7+- sqrt(57))/2}}}---- either of these if you want real numbers only.