Question 891981
Solve for x.
{{{ log( 2, x+1 ) }}} = {{{ log( 4, x+3 ) }}}
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{{{ log(4,x+3)}}} can be rewritten as {{{(1/2)log(2,x+3)}}}
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{{{log(2,x+1)}}} = {{{log(4,x+3)/2}}}
{{{2log(2,x+1)}}} = {{{log(2,(x+3))}}}
{{{(x+1)^2 = x+3 = x^2 + 2x + 1}}}
{{{x^2 + x - 2 = 0}}}
(x-1)*(x+2) = 0
x = 1
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x = -2 is rejected, gives log of a neg value