Question 891794
(wondering how segment BD got in there when the triangle is ABC)
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{{{a^2}}}+{{{b^2}}}={{{c^2}}}
You're given C as 10 cm
You're given one leg as 4.8cm
You're asked to find the other.  Let's plug in the known values.
{{{a^2}}}+4.8^2 = 10^2
{{{a^2}}}+ 23.04 = 100
Subtract 23.04 from each side
{{{a^2}}} = 76.96
Take the square root of each side
a = 8.77 cm (rounded)