Question 891700
log8-logx-log(x-2)=-1
add -log8 to each side
 -logx - log(x-2) = -1 -log8
multiply each side by -1
 logx + log(x-2) = 1 + log8
Assuming log means log base 10
 log(x) + log(x-2) = log(10) + log(8)
log(x(x-2)) = log(10*8)
log(x(x-2)) = log(80)
 x(x-2) = 80
 x^2 -2x = 80
 x^2 -2x -80 = 0
 (x-10)(x+8) = 0
so x = 10