Question 891698
Let x = the first integer
x + 1 is the second
x + 2 is the third
(x) + (x+1) + (x+2) = 267
3x + 3 = 267
add -3 to each side
 3x = 264
divide each side by 3
 x = 88
so the numbers are 88, 89 and 90